(2t^2+3t-4)(8t+1)=0

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Solution for (2t^2+3t-4)(8t+1)=0 equation: 


Simplifying
(2t2 + 3t + -4)(8t + 1) = 0

Reorder the terms:
(-4 + 3t + 2t2)(8t + 1) = 0

Reorder the terms:
(-4 + 3t + 2t2)(1 + 8t) = 0

Multiply (-4 + 3t + 2t2) * (1 + 8t)
(-4(1 + 8t) + 3t * (1 + 8t) + 2t2 * (1 + 8t)) = 0
((1 * -4 + 8t * -4) + 3t * (1 + 8t) + 2t2 * (1 + 8t)) = 0
((-4 + -32t) + 3t * (1 + 8t) + 2t2 * (1 + 8t)) = 0
(-4 + -32t + (1 * 3t + 8t * 3t) + 2t2 * (1 + 8t)) = 0
(-4 + -32t + (3t + 24t2) + 2t2 * (1 + 8t)) = 0
(-4 + -32t + 3t + 24t2 + (1 * 2t2 + 8t * 2t2)) = 0
(-4 + -32t + 3t + 24t2 + (2t2 + 16t3)) = 0

Combine like terms: -32t + 3t = -29t
(-4 + -29t + 24t2 + 2t2 + 16t3) = 0

Combine like terms: 24t2 + 2t2 = 26t2
(-4 + -29t + 26t2 + 16t3) = 0

Solving
-4 + -29t + 26t2 + 16t3 = 0

Solving for variable 't'.

The solution to this equation could not be determined.

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